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Mechanika – képletgyőjtemény (középszint) Mozgástan: sösszes tösszes s = v ⋅t vá = ∆v a= t t T= Z v + v0 vá = 2 Z f = t acp = v = v0 + a ⋅ t T= vk2 = ω 2 ⋅ R = ω ⋅ vk R ω= v 2 − v02 v + v0 s= s= ⋅t 2⋅a 2 i 2 Rπ vk = = = 2 Rπf t T a s = v0 ⋅ t + ⋅ t 2 2 i α rad = R 1 f α rad ω = 2πf = t 2π T vk = ω ⋅ R Erıtan ∆I m Fe = m ⋅ a Fe = ∆t V A lendület megmaradás törvénye: Zárt rendszerben ( ∑ Fkülsı = 0 ) a testek lendületének vektori összege idıben állandó. ρ= I = m⋅v Fg = Fn = m ⋅ g Fs = µ ⋅ Fny Fr = D ⋅ x = D ⋅ ∆l Fkö = Fs 0 = µ0 ⋅ Fny 1 ⋅c ⋅ ρ ⋅ A⋅ v2 2 vízszintes felület: Fny = m ⋅ g G = m ⋅ (g ± a ) Fcp = m ⋅ a cp F f = ρ folyadék ⋅ Vkiszorított ⋅ g m1 ⋅ m2 r2 Fm = m ⋅ g ⋅ sin α Tömegvonzás: Fg = f ⋅ Kepler III. törvény: Lejtı: Fny = m ⋅ g ⋅ cos α ale = g ⋅ (sin α − µ ⋅ cos α ) T12 a13 = T22 a23 a fel = − g ⋅

(sin α + µ ⋅ cos α ) Merev test egyensúlya M = F ⋅k Egyensúlyi feltételek: ∑F = 0, ∑M = 0 Mechanikai munka, energia, teljesítmény W = F ⋅ s ⋅ cos α Pá = W ∆E = t t m⋅ v2 2 Vízszintesen: WFs = − µ ⋅ m ⋅ g ⋅ s Lejtın: WFs = − µ ⋅ m ⋅ g ⋅ s ⋅ cosα P = F ⋅v m⋅ v2 Em = 2 Wgyorsítás = Eh = m ⋅ g ⋅ h η= Whasznos P = h Wbefektetett Pb W feszítı = D ⋅ x2 Er = 2 F ⋅ x D ⋅ x2 = 2 2 Wemelés = mgh Wrugó = ± WFg = ± mgh D ⋅ x2 2 E = Em + Eh + Er Munkatétel: ∆E m = ∑W Mechanikai energia megmaradása: Ha csak konzervatív erık hatnak (pl. Fg és/vagy Fr) ⇒ E=állandó Szerzı: Varga Zsolt 2010.0507